34t=16t^2

Solution for 34t=16t^2 equation:

34t=16t^2

We move all terms to the left:

34t-(16t^2)=0

determiningTheFunctionDomain
-16t^2+34t=0

a = -16; b = 34; c = 0;
Δ = b2-4ac
Δ = 342-4·(-16)·0
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-34}{2*-16}=\frac{-68}{-32}
=2+1/8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+34}{2*-16}=\frac{0}{-32}
=0
$